1=0.6x^2-3.2x+4

Solution for 1=0.6x^2-3.2x+4 equation:

1=0.6x^2-3.2x+4

We move all terms to the left:

1-(0.6x^2-3.2x+4)=0

We get rid of parentheses

-0.6x^2+3.2x-4+1=0

We add all the numbers together, and all the variables

-0.6x^2+3.2x-3=0

a = -0.6; b = 3.2; c = -3;
Δ = b2-4ac
Δ = 3.22-4·(-0.6)·(-3)
Δ = 3.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3.2)-\sqrt{3.04}}{2*-0.6}=\frac{-3.2-\sqrt{3.04}}{-1.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3.2)+\sqrt{3.04}}{2*-0.6}=\frac{-3.2+\sqrt{3.04}}{-1.2}
$